MGA android jobs (salary & requirements)

MGA android salary range: 30K - 50K, where 100% of positions earn ¥30-50K

￥30-50K

100% of positions earn

Note: the average salary is analyzed based on job postings published by the company. We recommend reviewing it together with position type, education, region and experience.

MGA android salary changes over the years

Note: the data depends on salary samples of online job postings in the corresponding years and does not fully represent the actual situation within the company. For reference only.

Education requirements: 本科 is the most common

100% 本科

What education does MGA require for android positions? 本科占比最多，占100%

Salary by education

本科￥40.0K

MGA android salaries by education: 本科 ¥40.0K.

Experience requirements: 3-5年 is the most common

33.3% 3-5年 33.3% 5-10年 33.3% 不限

What experience does MGA require for android positions? 3-5年占比最多，占33.3%，5-10年占33.3%，不限占33.3%

Salary by experience

MGA android salaries by experience: 3-5年 ¥40.0K, 5-10年 ¥40.0K.

MGA android hiring regions: mainly 北京, 广州

北京￥40.0K 33.3%(1) 򀀩

广州 򀀩

成都 򀀩

In which cities does MGA have offices for android positions? The main distribution is as follows: 北京 accounts for 33.3%. Click this module to view the proportions of other cities, based on job postings in the past year. For reference only.

MGA android hiring trends over the years

MGA android changes in hiring volume over the years

What does MGA android do

Based on related job postings of MGA in the past year

android高级开发工程师
广州-天河区 | 本科以上 | 2025-09-26
40000-55000元

1. 负责智能电视产品系统架构设计、路线规划以及性能优化、新技术方向等专题；

2. 负责智能电视系统性能优化方案的设计，执行和推动及相关文档的输出；

3. 负责技术洞察及相关技术规划。

任职要求：

1. 10年以上Android系统/Linux内核相关开发经验，有同岗位任职经验者优先；

2. 对Android性能全栈有全面的认知，有实际的底层性能优化经验，熟悉系统性能瓶颈，掌握profile方法，有完备的底层技术栈知识储备；

3. 熟悉Linux内核框架，对进程调度，内存管理，文件系统，网络等子模块有深刻理解；

4. 熟悉芯片平台类稳定性问题分析，有Bus hang、DDR hang、CPU hang等平台类问题分析经验；

5. 对技术充满热情，自我驱动，敢于创新，注重团队合作。
More
android/安卓开发工程师
成都-双流区 | 3-5年 | 本科以上 | 2025-09-26

20000-40000元 򀀩
android系统工程师
北京-朝阳区 | 5-10年 | 本科以上 | 2025-09-26

30000-50000元 򀀩