知识视觉本科 salary overview

How is the salary and benefits at 成都知识视觉科技有限公司本科? Are the salaries high at 知识视觉本科?Salary range: ¥4.5K-15K, with 84.6% of positions earning 6-10K,

知识视觉本科 salary range: 4.5K - 15K, where 84.6% of positions earn ¥6-10K

7.7% 4.5-6K ***  ? 6-8K ***  ? 8-10K 7.7% 10-15K

Note: the salary statistics for 成都知识视觉科技有限公司本科 are based on 13 salary records from the past year. The data depends on the position samples and is for reference only.

￥6-10K

84.6% of positions earn

Note: the average salary is analyzed based on job postings published by the company. We recommend reviewing it together with position type, education, region and experience.

知识视觉本科 salary changes over the years

Note: the data depends on salary samples of online job postings in the corresponding years and does not fully represent the actual situation within the company. For reference only.

成都知识视觉科技有限公司本科Salary range: 4.5-6K: %, 10-15K: %. . Disclaimer: statistics are based on job posting analysis and do not represent the actual situation of current employees; system stability may affect objectivity, so please treat the data as reference only. Data inaccurate? Report it

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Salaries for hot jobs of 知识视觉本科

Are salaries high at 成都知识视觉科技有限公司本科? We provide: 理赔, java, 全栈开发, 功能测试, 审核, 开发工程师, 测试工程, 全栈工程师. Click to view detailed salary analysis by job.

知识视觉本科 salary list/ranking

Position Region Salary↓ (posted by company)

理赔审核成都 5000-9000 Average salary
保险理赔录入成都 4000-9000 Average salary
科研助理(医学相关) 成都 4000-6000 Average salary
行政成都 4000-9000 Average salary
人身险理赔专员成都 4000-9000 Average salary
理赔审核成都 5000-9000 Average salary
理赔专员成都 5000-9000 Average salary
初级Java全栈开发工程师成都 7000-11000 Average salary
初级测试工程师（功能测试方向）成都 6000-10000 Average salary
测试工程师（功能测试方向）成都 6000-10000 Average salary
Java全栈开发工程师成都 7000-11000 Average salary
java全栈工程师成都 8000-13000 Average salary
医疗审核成都 5000-10000 Average salary

Note: 知识视觉 employee salarydata is collected from public salary information published on various websites by the company in the past year. For reference only.